Tweets about ‘Electronics’

 

Posts in the ‘Electronics’ Category

My new Crackberry

March 6th, 2009

crackberry2 I think I have been really patient. I’ve stayed away from surfing on my Sony w810, and used my Dell Laptop’s Telus evdo modem to get my fix while we’ve been on the road. But after I drove over the w810 (actually it dropped out of my pocket while I was pulled over on the side of the road having a pee, then I probably peed on it, and then I drove over it… oops) the screen has been dying little by little.

I was tagged for an upgrade to a Blackberry, and we went in to check them out. It turned out for 99 bucks, I could get a Blackberry Bold 9000, so I said yes plz.

Being able to surf and look at stuff, receive emails, and update web pages from anywhere rules! In the places I hang out, if you pull a net laptop out, it’s a conversation starter, but now, I’m just another loser addicted to playing with his phone in public. Hah!

Electronics 2 comments

Power Amplifiers

January 28th, 2007

Power amplifiers are typically used in the final output stages of circuits. In communications, they can be hooked up to an antenna or a transmitter, and in audio, to provide signal power to a speaker system. As the name implies, they dissipate large amounts of power, so heat sinks or cooling fans are important. They are physically larger than small signal transistors, and may have cooling fins built in. Power amplifiers deliver power to the load. Therefore the power gain (Ap) is the ratio of the power to the load (Pl), to the input power (Pin).


Ap = Pl/Pin

where:
Pl is the load power, calculated by


Pl = Vl^2/Rl

and Pin is the input power, calculated by

Pin = Vin^2/Rin

Rin being the input resistance.

This is usually expressed in RMS, which is .707 times the peak voltage. If you measure AC voltage with an RMS voltmeter, this is the way to calculate load power. More often you are looking at the AC output voltage with an oscilloscope. In this case use

Pl = Vpp^2/8Rl

When the voltage gain is known, another equation that can be used is

Ap = Av^2(Rin/Rl)

Assume a common collector amplifier has an input resistance of 10k ohms, and a load resistance of 100 ohms. Voltage gain is approximately one for common-collector, so the power gain is

Ap = 1(10k/100)
Ap = 100

The AC and DC load line

AC load lineDuring the positive half cycle of ac source voltage, the collector voltage swings from the Q-point towards saturation. During the negative half cycle, the collector voltage swings from the Q-point towards cutoff.

Maximum output voltage can be achieved when the Q-point is at the center of the AC load line. This differs from the DC load line in amplifiers (common emitter for example) because the DC and AC collector resistances are not equal. The DC collector resistance is simply the collector resistance, where the AC collector resistance is the collector resistor in parallel with the load resistance.

In the image of the AC load line for a CE amplifier, point a is the AC saturation point, and is calculated by

Icq + (Vceq/Rc)

and point b is the AC cutoff, calculated by

Vceq + IcqRc

DC quiescient power

Pdq = (Icq)(Vceq)

This is saying the power dissipation of a transistor with no signal input will just be the product of q-point Ic and Vce. Class A power amplifiers must maintain a quiescient current that is at least as large as the peak current requirement for the load current. The output power is

Pout = Vl(rms)Il(rms)

This formula can be used to determine the output power maximum.

Pout(max) = .5(Vceq)(Icq)

The Efficiency of an amplifier is the ratio of the signal power to the load, to the power supllied from the DC source.

%Eff(max) = (Pout/Pdc)100

Classifications of Power Amplifiers

There are a few classifications of power amplifiers, and they are based on the percentage of the input cycle that the amplifier operated in the linear region. In the previous examples, reaching cutoff or saturation was undesirable and resulted in clipping and distortion.

Amplifiers operating solely in the linear region are known as Class A amplifiers. They are usually mid-point biased to maximize the available gain. Any distortion or clipping is undesired. They are usually constructed in a common-emitter or common-source configuration. The amplifier conducts for the full 360 degrees of the input cycle, always in the linear region, and the output wave is 180 degrees out of phase with the input. Class A efficiency is usually around 25%.

Class B amplifiers have the q-point at cutoff. For this reason, they operate for 180 degrees of the input signal, and since Icq = 0 and Vce = Vce(cutoff), the transistor is not conducting until an AC signal is applied. Two transistors are usually used in class B amplifiers to create a push-pull configuration. Each transistor conducts for 180 degrees of the input signal, and the full signal is sent to the load. Class B amplifiers have a 79% maximum efficiency.

Bipolar junction transistors have the .7 (silicon) or .3 (germanium) volt drops that must be overcome, or the signal becomes distorted as it flips between the two transistors. This is known as crossover distortion. Diode biasing can be used to overcome it. The diodes compensate for the base-emitter voltage drops and produce a undistorted signal.

Class AB is a modified form of Class B push-pull operation when biasing resistors are used to put the push-pull stages into slight conduction, even when there is no input signal applied.

Basic Class C amplifiers are biased so they conduct for even less than 180 degrees of the input cycle. More power can be obtained, but the output is very distorted, and so Class C is used more often in RF applications. They are biased way below cutoff, and therefore much less heat is generated from this momentary conduction. A negative voltage is applied from the base, and the transistor conducts only when Vin exceeds this negative voltage and the voltage from the base to the emitter.

Power dissipation is very low for a class C, and can be found through

Pd(avg) = (time on/T)(Vce(sat)Ic(sat))

Remembering that the voltage drop across a transistor is around .2 volts, this will usually be a pretty small amount.

In tuned operation, a tank circuit containing an inductor and a capacitor set for resonance is used. This tank circuit would normally start out at a full wave form, and then slowly discharge with one pulse from the input. These circuits are tuned so each pulse from the input keeps the oscillation of the tank circuit going. Efficiency for Class C operation can approach 100%!

Electronics, Math No comments

FET Amplifiers

January 18th, 2007

Field Effect Transistors (FETs) can be used as amplifiers, much like the Bipolar Junction Transistors (BJTs) studied earlier. The difference is instead of being current controlled, they are voltage controlled. FET’s are just a current source that are controlled by Vgs. The different configurations of FET amplifiers even have similar characteristics to their BJT counterparts. Before looking at the different configurations, lets look at what makes a good FET amplifier, and the formulas used.

The transconductance curve for a FET is a comparison of values of voltage from gate to source (Vgs) to values of drain current (Id). When Vgs is closest to Vgs(off), which means the transistor is no longer conducting, then Id is at a minimum. When Vgs = 0, then Id is at it’s maximum, Idss. Idss is the drain current with the source shorted, which under normal conditions, is the highest amount the transistor will let flow.

Vgs(off) you get Id at a minimum
Vgs = 0 you get Idss (Id maximum)

The different types of JFET’s and MOSFET’s are detailed in my other posts so I won’t go into it too much here. Until further mentioned, I am going to assume a mid-point biased JFET transistor. This gives a bit of distortion due to the transconductance curve, but is acceptable for some applications. When less distortion is needed, D-Mosfets, which operate in either depletion or enhancement mode, the area around Idss can be a fairly linear and therefore a good spot to bias for amplification. For now, I’ll just stick to JFET’s.

The main advantage to FET amplifiers is their high input resistance. Since the gate to source junction is reverse biased, it has as much input resistance as a reverse biased diode.

Gain is still and can always be defined as the ratio of Vout/Vin. In the case of a FET amplifier, it can also be defined as

Av = Vds/Vgs

Gain can also be determined using transconductance (gm) measured in Siemens (S) times the value of the drain resistor (Rd). Remember that in the case of a loaded amplifier, the drain resistor is parallelled with the load resistance (Rd = RD || RL).

Av = gmRd

gm0 is a value given on datasheets, and represents the value of gm measured at Vgs = 0. From this, you can calculate values of gm for different values of Vgs.

gm = gm0 (1-(Vgs/Vgsoff))

There are three main configurations. Common-Source, Common-Drain, and Common-Gate.

In FET Common-Source amplifiers, the DC and AC share a common point at the source of the transistor, and share a lot of the characteristics of the Common-Emitter BJT. The signal at the output has a 180 degree phase shift from the input, and some voltage gain.

In FET Common- Drain amplifiers, the DC and AC share a common point at the drain, and can be compared to BJT Common-Collector amps. Vout is in phase with Vin, and the voltage gain is ~1. They are current amplifiers, and are also referred to as source-followers.

In FET Common-Gate amps, the gate is the common point for DC and AC, and can be compared to Common-Base BJT’s. They have a low input resistance. Common-Gates are mostly used for high frequency circuits, often as the first stage, and sometimes connected directly to an antenna.

Electronics 3 comments

JFET Transistors

January 4th, 2007

The Junction field effect transistor

JFET’s are constructed in two types. They can either be N-channel, or P-channel. In an N-channel JFET, There is a solid layer of N-type semiconductor, with two layers of P-type material attached to the sides. These two P-type materials are calledd the gate, and the two ends of the N-type material are called the source and the drain.

In diagrams, the drain is at the upper end, and the source is at the bottom end. Currrent in the drain circuit flows from the source to the drain.

The JFET is always operated with the gate-source junction reverse-biased. This reverse biasing of the gate-source junction with a negative gate voltage produces a depletion region in the p-n junction, which extends into the N-channel and increases the resistance between the source and the drain terminals.

In an example with two power supplies, one is attached from the drain to the sourceand is called Vdd, and is known as the drain circuit. The negative terminal is connected to ground, as well as to the source of the JFET. The positive end is connected to a series limiting resistor (Rs) and also to the source terminal of the JFET.

The gate supply (Vgg) is connected with the positive end to ground, and the negative end to the gate. This creates a negative gate voltage, which is needed for the reverse biasing of the gate source pn junction.

A greater value of Vgg narrows the channel, which increases the resistance of the JFET, and decreases drain current (Id).

Less Vgg widens the channel, which decreases resistance and increases drain current(Id).

Pinch-off voltage

The Pinch-off voltage (Vp) is the value of voltage from drain to source at which drain current (Id) becomes constant. In this area, known as the constant-current area, drain current will remain constant until it reaches breakdown. Once breakdown occurs, the JFET is being operated out of range and current will increase quite rapidly until it is destroyed.

Cutoff voltage

The value of voltage from the gate to the source that produces a drain current of approximately zero is called the cutoff voltage, or Vgs(off). For N-channel JFET’s, this will be a negative voltage, and this causes the delpetion region to become so large that current flow is stopped.

There is a relation between the pinch-off voltage and the cutoff voltage. Vgs(off) and Vp are always equal, but opposite in sign. That is, if Vgs(off) is -3 volts, then pinch-off voltage is 3 volts.

to be continued…

Electronics No comments

Ti Calculators

December 4th, 2006

I have a Ti 35 (not shown) and a Ti 89 platinum (below). I use TiLP to transfer files to and from my TI 89 and my Ubuntu box.

dsc00066.JPG

Links:

Ticalc.org

Backlighting

Electronics, Math, Ti Calculators, Ubuntu No comments

Diodes

November 20th, 2006

diode.jpgThe simplest way of describing a diode is a single P-N junction with a lead attached to each end. The end with the N-type material is named the Cathode, and the end with the P-type material is known as the Anode. Diodes (and other semiconductor devices) behave differently than simple resistors due to the fact they are non-linear, which means their current is not directly proportional to their voltage. When you have a simple resistive circuit, current proportional to voltage is plotted on a straight line, and is therefore linear. The graph of a diode has a certain point where it begins to conduct, and also a reverse point where it starts to breakdown.

Starting with the forward region, once the biasing voltage source overcomes the barrier potential, the diode begins to allow electron flow. For a normal doped silicon diode, this is .7 volts. This is also known as the knee voltage, because once .7 volts is achieved, the voltage on the graph turns very sharply up, creating what looks like a knee in the line. Above the knee voltage, diode current increases very rapidly. Once the barrier potential is overcome, all that impedes the flow of current is the resistance of the P and N junctions. This is called the Bulk resistance of the diode and can be calculated from the sum of the resistance of the P and N junctions.

Another thing to consider in the forward region is the maximum DC forward current. This can be found on datasheets. Once this is achieved, the diode will probably be destroyed due to excessive heat. This is usually termed If(max) or Io. Diode datasheets also have a maximum power disspation rating.

When diodes are operated in the reverse region, you get a very small amount of leakage current, and there is a point when the diode will breakdown, due to an effect called avalanche. When so many electrons are being forced onto the diode, the energy that propels them is enough to force other electrons out of their valence band and across the P-N junction. This breakdown voltage is also put on the datasheet. Although some specialty diodes, like zener diodes are meant to be operated in this way, on a normal diode, avalanche is to be avoided.

Special purpose diodes

Rectifier diodes are constructed to allow current in only one direction. when used with an AC voltage source, this cuts off one side of the sine wave, and creates a pulsating DC wave. Say the circuit is connected so only the positive alternations are passed, once the sine wave reaches 0 volts, it remains there until the wave reaches 0 volts again, and then continues on passing a positive sine.

This arrangement of a diode in a circuit is known as a half-wave rectifier.

halfwave.jpg

latex014.gif

where:
Vp is your peak voltage
Vs is your voltage source
and .7v is the voltage drop across the diode (silicon).

If you arrange a diode this way on both ends of a AC voltage circuit and then combine them, you get what is known as a full-wave rectifier. Only the positive waves are passed, and they are 180 degrees out of phase with each other. The end effect is as the positive sine wave of the first signal drops to zero, the other side pulses and completes it’s sine, and so on. the result ends up looking like a regular sine wave, with the negative alternations flipped positive. Full-Wave rectifiers can be used in power supplies, where an AC signal is provided and a DC voltage is desired. Full wave rectifiers must use a center tapped transformer.

fullwave.jpg

Since the negative alternations are simply dropped, normal full-wave rectifiers are wasteful. When designing a rectifier circuit, it is better to use a bridge rectifier. Bridge Rectifiers have two ways for the current to flow, so there is a path on each alternation. Most power supplies use this configuration. Since a center tap is not needed, the rectified voltage is twice what a full wave recifier would create.

bridge.jpg

In bridge rectifiers, another thing to consider is since you have two diodes dropping voltage on each path, the voltage is calculated by:

latex015.gif

where:
Vp is your peak voltage
Vs is your voltage source
and 2(.7v) is two .7 voltage drops across the diodes (silicon).

If you connect a DC Voltmeter across the load, it will indicate the average value of the full wave signal, which is:

latex017.gif

which is equivalent to

.636 * peak voltage.

The frequency of a full wave signal is double the input frequency, since a waveform completes it’s cycle as soon as it repeats. For a 60 hertz input:

Time = 1/Frequency

Time = 1/60

Time = 16.7ms

The rectified voltage has a period of

Time2 = 16.7ms/2

Time2 = 8.33ms

Frequency2 = 1/8.33ms

Frequency2 = 120 hertz.

Another way to put this simply is to say:

Fout = 2Fin

where:
Fin is Frequency In
Fout is Frequency Out

zener.jpgAnother type of diode is the Zener diode. Most diodes are never operated in the breakdown region beacuse it would damage them. A zener is manufactured to be operated in the reverse region, and to have a specific voltage where it will begin to conduct. Zener’s are available in many different voltages. A zener diode is sometimes referred to as a zener voltage regulator becuase they can be used in parallel to allow a certain voltage to pass to the load, and then begin to conduct once the zener voltage is reached, therefore passing the remaining voltage through the zener and bypassing the load. A series resistor is always used in this configuration to limit current flow.

Maximum power through a zener diode is found by:

latex018.gif

Zener Impedance can be found through:

latex022.gif

The change in Zener voltage (^Vz) can be found by:

latex023.gif

led.jpgLED’s or light emitting diodes are another specialty diode. As the electrons cross the P-N junction and fall into holes, they radiate energy. LED’s are constructed to show this as visible light. By using elements like arsenic and phosphorus, LED’s can be manufactured in red, green, yellow, blue, orange and even infrared. The exact voltage drop across LED’s depends on the color. The typical voltage drop is 1.5 to 2.5 volts for currents between 10 and 50 milliamps.

All diodes have an associated capacitance, due to the way they are constructed. The P and N regions can be thought of as the plates, and the depletion region is the dielectric. Varactor diodes are built to take advantage of this, and are used in tuning circuits where a variable resonant frequency is desired. As the voltage is varied, the depletion region expands and contracts, causing the capacitance to change. You can connect a varactor in parallel with an inductor to get a resonant circuit, and then vary the biasing voltage to achieve specific resonant frequencies.

Electronics No comments

Semiconductors

November 20th, 2006

Since conductors have a single valence electron, and insulators have a full valence ring of eight electrons, it makes sense that semiconductors such as silicon have four valence electrons. This also means that there is four spots for valence electrons in a silicon atom. When atoms of silicon combine they create covalent bonds. Co as in shared, and valent, meaning valence electrons. The result is a silicon crystal, which can be thought of as a lattice of silicon atoms, all connected by their shared electrons.

Doping is the process of adding impurities to silicon (or other semiconductors) to alter the electrical characteristics of the semiconductor. If we think of a pure, or intrinsic piece of silicon, there is ideally no free electrons, and no free “holes” in the valence bands for electrons to go.

We add an atom with 3 valence electrons. Elements with 3 valence electrons are aluminum, boron, gallium, and indium. This creates a tri-valent bond and leaves on open “hole” for an electron to flow in and out of. Doping a semiconductor this way creates a P-type material. To remember, you can think of the “P” as positive. There is a deficiency of one electron, so the 3 valence atom added is known as a acceptor impurity element.

The other method of doping is to add an atom with 5 valence electrons to a piece of silicon. Elements with 5 valence electrons are arsenic, antimony and phosphorus. This creates a crystal with an extra electron that is free to move around and is known as a penta-valent bond. This is known as a N-type material and can likewise be remembered that the “N” is for negative. There is an extra electron, so the 5 valence atom is known as a donor impurity element.

As you can see, the amount of impurities added directly effects the electrical characteristics, and can be used to regulate the amount of electrons moving through the material. Simply having a P or N type material on their own might have some uses, but when the two are used together, a P-N junction is formed, and is the basis of many electronic devices used today.

When the two materials are put together, they repel each other. The free electrons spread out, and some of them diffuse across the junction. This is known as the depletion region. Each time an electron crosses over, it leaves a pentavalent ion, with a relative positive charge. This electron in turn falls into a hole in the P-type material, and causes a negatively charged trivalent ion. It has space for one electron, and when it is filled we can say that it has gained a relative negative charge. This region, with positively charged extra electron ions, and negatively charged electron deficient ions, creates a potential difference between them. This is known as barrier potential. The barrier potential is usually .7v for silicon, and varies for other types of semiconductors. The basic idea is exactly the same though.

The barrier potential must be overcome to allow electron flow in the P-N type material. Biasing a P-N junction is the process of adding a voltage source to either allow or prevent the flow of electrons.

When the N-type is negative with respect to the P-type material, the electrons easily flow from the power supply, to the junction, then from one side to the other. The N-type material constantly feeds the electrons to the P-type, and the electrons flow from the p-type back to the power supply. This is known as forward bias. The P-N junction is arranged in the circuit to allow electron flow.

Reverse biasing is done by changing the polarities of the voltage source, so the negative terminal is connected to the P-type, and the positive terminal is connected to the N_type material. This causes the depletion layer to widen, because the negative terminal attracts the free “holes” and the positive terminal attracts the free electrons. Current is not allowed to flow.

So far we have been looking at this in a perfect world, but in reality, there are a few holes in a N-type material and likewise there is a few extra electrons in a P-type material. These are known as the minority carriers, and are mostly caused by thermal energy, or heating of the P-N junction. Under normal operating temperatures, this amount is negligible. Datasheets are invaluable when seeking the maximum temperatures, voltages, and dissipation of power for any electronic device.

Electronics No comments

RLC circuits

November 8th, 2006

RLC circuits are named after the components that they contain. Resistors (R), Inductors (L) and Capacitors (C). In these circuits, there are two separate reactances, both opposing each other. In series RLC, the inductive voltage (Vl) is leading the current (I) by up to 90 degrees. The capacitive voltage (Vc) is lagging the current by up to -90 degrees. So what we have is two reactances, working to cancel each other out. Luckily enough, this is exactly how we calculate them.

The lower of the two reactances is subtracted from the higher one. Say Xl is 100 ohms, and Xc is 75 ohms, the resulting reactance (Xnet) is 25 ohms, and since the resulting reactance is Xl, we say the circuit is acting inductively. Likewise, if Xc is greater than Xl, after we subtract one from the other, we say the circuit is acting capacitively.

It is easier to remember this by looking at vector diagrams. Current is once again our reference vector, with resistance in phase on the horizontal, inductance is plotted upward, and capacitance plotted downward. Whether we are talking voltages (Vl/Vr/Vc/Vt) or resistance (Xl/R/Xc/Z), in series circuits, the vectors look the same.

When applying the pythagorean theorem to series RLC, we simply subtract the reactances, and use the remainder (Xnet) in the formula. First subtract lesser reactance from the greater.

latex012.gif

or

latex013.gif

and then

latex009.gif

same thing for reactances to calculate impedance.

Xl – Xc or Xc – Xl = Xnet

Z = √(R^2 + Xnet^2)

An example to calculate Impedance in Series RLC:

rlc1.JPGR = 100 ohms
Xl = 75 ohms
Xc = 60 ohms

75 – 60 = 15 ohms = Xnet

√(100^2 + 15^2) = 101.119 ohms = Z

Tan-1( 15 / 100 ) = 8.53 degrees = Phase angle

Say we had an applied AC voltage of 20 volts @ 100Hz . First calculate total current using Ohm’s law. I = V / Z.

rlc2.JPG20 / 101.119 = 197.787 mA

From there we can calculate the voltage drops across the components

Vr = .197787 * 100 = 19.7787 volts
Vl = .197787 * 75 = 14.834 volts
Vc = .197787 * 60 = 11.8672 volts

As you can see, there is a lot of voltage here, but Vl and Vc are canceling each other out. Working through it again, we can double check our work.

rlc3.JPGVl – Vc = Vnet
14.834 – 11.8672 = 2.9668 volts

√(19.7787^2 + 2.9668^2) = 20 volts = Vt

Tan-1( 2.9668 / 19.7787 ) = 8.53 degrees. It checks out.

Parallel RLC circuits

Once again, the reactances cancel each other, the same way as in series, but in parallel circuits, voltage is our reference vector (since the same voltage flows though each branch) and is plotted horizontally, along with resistive voltage (in phase). Capacitive current leads the voltage by up to 90 degrees (ICE) and inductive current lags the voltage by up to -90 degrees.

An example of a parallel RLC circuit. Let’s keep our 20 volts @ 100Hz and use:

R = 55 ohms
Xl = 225 ohms
Xc = 125 ohms

Say for simplicity, that each component is on it’s own branch. In a parallel circuit, we want to calculate branch currents first.

rlc4.JPGIr = Vt /R
Ir = 20 / 55
Ir = 363.636 mA

Ixl = Vt / Xl
Ixl = 20 / 225
Ixl = 88.8889 mA

Ixc = Vt / Xc
Ixc = 20 / 125
Ixc = 160 mA

We subtract Ixl from Ixc to get our net reactance current (Inet):

rlc5.JPG 160 – 88.8889 = 71.1111 mA = Inet

find total current through the pythagorean theorem:

It = √(Ir^2 + Inet^2)
It = √(.363636^2 + .07111111^2)
It = 370.524 mA

use arctan to solve for phase angle:

rlc6.JPGTan-1( .0711111 / .363636 ) = 11.0649 degrees = phase angle

and lets finish by calculating impedance from Ohm’s law.

Z = Vt / It
Z = 20 / .370524
Z = 53.9776 ohms

References:
Foundations of Electronics, by Russell L Meade

Electronics No comments

Complex Numbers in AC circuits

November 7th, 2006

Complex numbers are an easy way to perform mathematical computations with AC quantities. While you can use Trigonometry and the Pythagorean Theorem to solve for magnitudes and values, two notations exist to make life easier.

In rectangular notation, the complex number has two parts, one real and one imaginary. The real number represents the in phase and resistive element, and is plotted on the X-axis. The imaginary number, is represented on the Y-axis. To input an imaginary number on your calculator, you use the i button. The real number is input, followed by + or – depending on if the imaginary number is a positive or negative angle, then the imaginary number, followed by the i symbol. On my Ti-89, to show an i you press (2nd > Catalog). It ends up looking like this.

3 + 4i

This tells you that 3 is the Adjacent (horizontal axis) and 4 is the Opposite (vertical axis). If you input numbers in this fashion, and put your calculator in Polar form notation, it will give you the hypotenuse, and the phase angle, all at once.

rect1.JPGPolar form notation shows you the length (hypotenuse) and the angle of the resulting vector. The angle symbol on the Ti-89 is generated by the keystrokes (2nd > EE). In this example, you would see

5 ∟ 53.1301°

This can be confirmed by using the sin and cos functions.

5 * sin(53.1301°) = 4
5 * cos(53.1301°) = 3

With your calculator in Rectangular form, you can input polar equations and have them return a real number and an imaginary number. On my calculator I need to enclose the polar notation in brackets.

(5 ∟53.1301°) = 3 + 4 * i

polar1.JPGYou can also use built in functions on a Ti 89 to do these conversions on the fly. Press the catalog button and you will find â–ºRect and â–ºPolar. You can use these functions without changing the mode of your calc.

(5 ∟ 53.1301°) ►Rect
returns
3 + 4 i

and also
(3 + 4 i) â–ºPolar
returns
5 ∟ 53.1301°

Algebraic Operations in Rectangular notation

Addition (add the in phase terms, and add the out of phase terms)

10 + 10i
15 + 15i
———
25 + 25i

Subtraction (change the sign of the subtrahend and add each)

10 + 10i
-5 – 15i
———
5 – 5i

Algebraic Operations in Polar notation

Multiplication (Multiply the magnitudes and add the angles)

5 ∟ 30°
20 ∟ -15°
———-
100 ∟ 15°

Division (Divide one magnitude by the other and subtract the angles)

35 ∟ 60°
140 ∟ 20°

35 / 140 = .25
60° – 20° = 40°
so the answer is
.25 ∟ 40°

References:
Foundations of Electronics, by Russell L Meade
Basic Electronics, by Bernard Grob

Electronics No comments

Resonance

October 26th, 2006

After looking at Inductors and Capacitors and their reactances, I got to wondering why you would use both inductors and capacitors in a circuit when it seems they counteract each other. The answer is to create resonant circuits. The goal here is to create a circuit with equal inductive reactance (Xl) and Capacitive reactance (Xc).

Lets start with series resonance. In inductive reactance, the voltage leads the current (ELI) by 90 degrees. In capacitive reactance, the current leads the voltage (ICE) by 90 degrees, or to be more precise, the voltage lags the current and creates a negative phase angle. Current is our reference vector and is plotted on the horizontal axis.

Characteristics of series resonance

  • Xl = Xc
  • Impedance (Z) is at a minimum because the inductive and capacitive elements are counteracting each other. This causes Z to equal Resistance (R)
  • Current (I) is at a maximum and equals V/R
  • Phase angle is 0 degrees since the circuit is acting completely resistive.

The inductive voltage (Opp at +90 degrees) is leading the current and resistive voltage (our reference vector, the Adj, etc.) and the Capacitive voltage is lagging the current and resistive voltage by -90 degrees (also the Opp).

Remembering the formula used in calculations of frequency when dealing with inductive reactance,

f = Xl/(6.28*L)

Where:
f = frequency in hertz
Xl = inductive reactance in ohms
L = inductance in henrys

and the formula for capacitive reactance.

f = 1/(6.28*C*Xc)

where:
f = frequency in hertz
Xc = capacitive reactance in ohms
C = capacitor value in farads

We need to combine them so we can get a formula to calculate resonant circuits.

fr = 1/(6.28 * √(L*C))

where:
f = frequency in hertz
C = capacitor value in farads
L = inductance in henrys

This, and the variations below, are formulas used to create series and parallel resonant circuits. If you have the Frequency (Fr) of the circuit and the capacitive value (C) you can calculate the inductor(s) needed by transposing the formula to the following.

L = .02533 / Fr^2 * C

and if you have the Frequency and the inductive value, you can use the formula

C = .02533 / Fr^2 * L

Q is known as a magnification factor or figure of merit. In general, the higher the ratio of reactance at resonance to the series resistance, the higher the Q. We can calculate Q from the following formula.

Q = Xl / Rs

where:
Q = Magnification Factor
Xl = Inductive reactance at the resonant frequency
Rs = resistance in series with Xl

Q can also be calculated by

Q = Vout /Vin

where:
Vout = ac voltage measured across the reactive element
Vin = applied voltage

Q will always be a positive number.

Characteristics of Parallel resonance

In parallel resonance,

  • Impedance (Z) is at a maximum
  • Tank current is current measured between the inductors and the capacitors and can be thought of as circulating from one to the other.
  • Line current is at a minimum
  • Xl = Xc
  • Phase angle is still 0 degrees

The same formulas for calculating series resonance apply here, just the results differ depending on whether the circuit is series or parallel. To calculate Q in a parallel resonant circuit, use

Q = Zt / Xl

where:
Q = Magnification Factor
Zt = total impedance
Xl = inductive reactance
Selectivity refers to the response curve of a resonant circuit. When resonance is achieved, the sharper the rise (and fall) of the curve, the more selective it is. For series resonance, the two points which current rises and falls to 70.7% of it’s maximum level is known as it’s bandwidth. For parallel resonant circuits, impedance (Z) is used.

Total bandwidth is calculated by the resonant frequency divided by the Q Factor.

BW = Fr / Q

where:
BW = bandwidth in Hertz
Fr = resonant frequency in Hertz
Q = Magnification factor

* Please note in these formulas, I am writing 6.28 as a rounded off version of two times pi. To get a truer number, it would be better to use (2 * pi).

References:
Foundations of Electronics, by Russell L Meade
Basic Electronics, by Bernard Grob

Electronics No comments

RL Circuits

October 24th, 2006

RL Circuits have a combination of Resistors and Inductors as their name would suggest. What we need to do is combine the resistive elements of our circuit with the reactive ones. Due to the way inductors behave, you cannot just add the resistors and inductive reactance, but you can use the pythagorean theorem, and you can also use vector mapping and basic trigonometry functions.

seriesrl.jpgSeries RL

In a series circuit containing resistors and inductors, the current (I) is our reference vector.

Resistors (R) are in phase, at 0 degrees. (Adj)
Inductive reactance (Xl) is at 90 degrees. (Opp)
Impedance (Z) is somewhere in between. (Hyp)

For calculating total voltage and, we use the same vector.

Resistor voltage (Vr) is in phase, at 0 degrees. (Adj)
Inductive voltage (Vl) is at 90 degrees. (Opp)
and total voltage (Vt) is somewhere in between. (Hyp)
The phase angle (Theta) is the angle between R and Z and can be calculated by

Tan-1(Opp/Adj) or in this case Tan-1(Xl/R)

This is most common in electronic circuits. However, sometimes you might only have the impedance and the resistance, and need to find the inductive reactance.

Cos-1(Adj/Hyp) so Cos-1(R/Z)

We can use a 3/4/5 triangle to quickly show how this works. Let’s say we need to find impedance, and Xl = 4, R=3.

Tan-1(4/3) = 53.130 degrees (This is your phase angle)

√(4^2+3^2) = 5 (This is your impedance)

5 * Sin(53.130) = 4 (Checking the angle by requesting the Inductive reactance (Opp).

parallelrl.jpgParallel RL

In parallel, Total voltage (V) is our reference vector on the horizontal (0 degrees) since the voltage is the same through each branch, and,

Resistive current (Ir) is in phase (0 degrees)

Inductive current (Il) is plotted downward (-90 degrees)

Total current (It) is plotted somewhere in between.

In parallel RL, you just use pythagorean to solve for impedance.

Z = √(Xl^2+R^2)

Electronics No comments

Fluke, a TI Calc, and good ol’ OpenBSD

October 3rd, 2006

I’ve kept an eye on Ebay for the last few weeks, paying special attention to the Business and Industrial: Test equipment (Canada only, 100 dollars and less) and have managed to score some decent multimeters. I got a pair of Mastercraft handheld multimeters (AC/DC voltage, DC current, resistance and diode) that are compact and very nice for the price (~10) and also a Fluke 8010a Bench Multimeter for 11 bucks that works perfectly.

7a_3.JPG

It’s been treated fairly decently, and was calibrated every two years by the Canadian Defense Department. Sweetness.

For calculators, there was nothing really spectacular in the used department online, so we checked out all the local stores and I picked up a Texas Instruments TI-89 Titanium. It Hooks up to the computer and I can transfer applications, equations, text files and pictures back and forth to the calculator via USB. Next I need to find the keyboard that plugs into it, so I can take notes on the road without lugging a laptop to school. Here’s a few screeners I took of the Desktop Apps, Word Processor, and a few electronics calculations.

screen01.JPG

screen02.JPG

screen03.JPG

But while I am just rambling on about stuff, I also got my old iBook 700 running OpenBSD 3.7 with X, and I have to admit, I like it alot better than OS X. I’m not trying to compare the two, but for what I need out of a laptop, FVWM and a couple of xterms just does it alot nicer than waiting for the beast that ate windows to start loading (and it runs a lot cooler too!). They didn’t do too much in the way of cooling for these little guys so the HD temperature gauge is my left wrist :P You can just feel that little HD burning away. Add to that it’s a lot more responsive, the CD drive works perfectly where It was quite stubborn before, and upgrades are free (well 50 bucks, cause I like to support the project, and my local store carries OpenBSD disks) and it beats the hell out of the upgrade path Mac had me on (buy!.. it’s obsolete… buy new!.. it’s obsolete, oh ya and your hardware won’t run the newy new. buy hardware and software! hmm.

Electronics, OpenBSD, Ti Calculators No comments

Inductance

October 1st, 2006

Inductance is a measure of magnetic flux for a given current, and it’s measurement is called the Henry (H). When we talk about inductance in electronics, we are talking about the ability to oppose a change in current flow. The lines of magnetic flux are exactly what produces this opposition. Energy is stored by an inductor in the form of a magnetic field surrounding it. Inductors are made of a conductor, coiled upon itself to produce a set amount of magnetic lines of flux. The opposition to the change in current produces a induced voltage. This can be thought of as a series-opposing voltage source. The amount of induced voltage (emf) depends on the rate of cutting the lines of flux. This is known as Faraday’s Law, and it’s formula is represented by:

Vind = d0/dT

Where:
Vind is the induced voltage (emf)
d0 is the rate of cutting the flux (in webers) and
dT is the change in time (seconds)
d is the symbol Delta, which represnts “the change in”

The four important physical elements that affect the amount of inductance are the coil length (number of turns per unit length), the cross sectional area of the coil, the amount of current through the coil, and the type of core material. Inductors can be made with an iron-core, like the ones commonly used for power supplies and audio circuitry, powdered iron-core, ferrite-core, or even just air-core. Each metal (or lack of, in the case of air-core)has a relative permeability and has some effect on the final inductance. iron-core inductors have typical ranges measured in Henry’s, powdered iron-core are usually found measured in milliHenrys (mH) and air-core inductors are usually found in the microHenry (uH) range.

The amount of induced voltage, also known as back-emf or counter-emf is related to the amount of inductance, and the rate of current change. This is more commonly known as self-inductance. The symbol for inductance is L. When we are talking about this oppostion to change, the formula to use is:

Vl = L * di / dt

Vl is our induced voltage in Volts
L is our inductance in Henry’s
di is the change in current, in amperes and
dt is the change in time, in seconds.

When using inductors in a circuit, you can apply many of the concepts you use with resistances in series and parallel. Total inductance in a series circuit is the sum of all inductances in it:

Lt = L1 + L2 + L3 … etc.

When finding the total inductance for a parallel circuit, it is also treted exactly the same as a resistance in parallel. you can either use the product over the sum, or the reciprocal method.

Lt = L1 * L2 / L1 + L2

or as with resistances, with more than two inductances in parallel:

1 / Lt = 1 / L1 + 1 / L2 + 1 / L3 … etc.

These formulas assume of course, that the inductors are non-coupled. This brings up the topic of mutual inductance. To quickly define non-coupled inductors, it refers to the magnetic fields (flux lines) of each inductor acting seperately, and not affecting each other.

Mutual Inductance is when you have two coils located near each other, and it causes the magnetic field of one to interact with the field of the other coil. This is how transformers work. This is usually the only place you want mutual inductance. In the case of seies or parallel inductors, any mutual inductance is undesirable.

References:
Foundations of Electronics, by Russell L Meade

Electronics No comments

Basic Network Theorems

September 20th, 2006

The superposition theorem

The superposition theorem states that in linear circuits having more than one source, the voltage across or current through any given element equals the algebraic sum of voltages or currents produced by each source acting alone with the other sources disabled.

Say there is two opposing voltage sources, and two resistors in a series configuration, for simplicity.

networktheorems12.jpg

Consider the second voltage source shorted, and calculate current, as well as voltage drops across resistors. We are going to treat each current, voltage source, and voltage drops across resistors seperately, and then subtract them, since they are opposing. Here is our circuit redrawn.

networktheorems2.jpg

The current flows from the negative (bottom) of V1, through R2, though R1, and back to the positive (top) of V1. So what we have is:

V1 = 12 volts

R1 = 75,000 ohms
R2 = 20,000 ohms
Rt = 75,000+20000
Total Resistance = 95,000 ohms

I1 = V1 / Rt
I1 = 12v / 95,000
Current produced by V1 = 126.316 uA

networktheorems7.JPGSo now we can calculate voltage drops across the series resistors, again using the rules for series circuits and Ohm’s law:

Vr1 = I * R1
Vr1 = 126.316 uA * 75k ohms
Vr1 = 9.4737 volts

Vr2 = I * R2
Vr2 = 126.316 uA * 20k ohms
Vr2 = 2.52632 volts

Then, do the same for the other voltage source, and make sure to keep track of the polarity, that is, the direction of current flow, and the polarity of each component. The current flows out of the negative (bottom) of V2, through R2, through R1, and back to the positive (top) of V2.

networktheorems3.jpg

V2 = 18 volts

R1 = 75,000 ohms
R2 = 20,000 ohms
Rt = 75,000+20000
Total Resistance is still = 95,000 ohms

I2 = V2 / Rt
I2 = 18v / 95,000
Current produced by V2 = 189.414 uA

networktheorems5.JPGAgain we calculate voltage drops across the series resistors, using the rules for series circuits and Ohm’s law:

Vr2 = I * R1
Vr1 = 189.414 uA * 75k ohms
Vr1 = 14.2106 volts

Vr2 = I * R2
Vr2 = 189.414 uA * 20k ohms
Vr2 = 3.78948 volts

networktheorems6.JPGThese two seperate calculations are then overlaid to find the voltage drops and currents at each component.

It = I2 – I1
It = 189.414 uA – 126.316 uA
Total current = 63.098 uA

Then calculate the voltage drop across R1

Vr1 = V2R1 – V1R1
Vr1 = 14.2106v – 9.4737v

R1 voltage drop = 4.7369 Volts

Vr2 = V2R2 – V1R2
Vr2 = 3.78948v – 2.52632v

R2 voltage drop = 1.26316 Volts

This was an example of the superposition theorem in a series circuit, using series opposing voltage sources. If the voltage sources are series aiding, meaning their polarities assist each other and current flows together, then you add the voltage drops at each component, and current produced. if they are series opposing, you subtract the amounts at each component.

This theorem can be applied to any series, parallel, or series-parallel circuit, using the same rules as a single voltage source and then adding or subtracting the results, depending if they aid or oppose each other. As circuits get more complicated and you get more components this becomes very handy.

Thevinin’s Theorem

Thevinin’s theorem states that any two terminal network (of resistances and sources) can be replaced by a simplified equivalent circuit consisting of a single voltage source (Vth) and a single series resistance (Rth).

Norton’s Theorem

Norton’s Theorem states that any linear two terminal network can be replaced by an equivalent circuit consisting of a single (constant) current source (In) and a single shunt (parallel) resistance (Rn).

The maximum power transfer theorem

Maximum power is transferred from the source to the load when the resistance of the load equals the resistance of the source. All power supplies have an internal resistance (Rint) and to transfer maximum power, we need to match this to the resistance of the load (Rl)

References:
Foundations of Electronics, by Russell L Meade

Electronics 2 comments

Parallel Circuits

September 16th, 2006

In a Parallel Circuit, there are two or more paths for the current to flow. Voltage in parallel circuits is the same across each Parallel branch. Each branch current is inverse to it’s resistance value, meaning the highest resistance value will have the least current flowing through it.

In parallel circuits, we substitute the current for the sum equals the total rule. The total current in a parallel circuit equals the sum of the branch currents.

It = I1 + I2 + I3… etc.

This is known as Kirchhoff’s current law. The value of current entering a point must equal the value of current leaving that same point.

As stated already, branch current is inverse to branch resistance. another difference in parallel circuits is the way total resistance is calculated. Whereas in a series circuit the total resistance is just the sum of all resistances, in a parallel circuit, the total (or equivalent) circuit resistance is always less than the smallest value branch resistance.

Knowing branch current, and total voltage, using Ohm’s law we can find each branch resistance.

R branch = V / I branch

Knowing each branch current, and each branch (total) voltage, we can calculate the equivalent resistance. To keep things simple, we will use the reciprocal method which is as shown below.

1/Req = 1/R1 + 1/R2 + 1/R3… etc.

There is also another method for use only with two branches called the product over the sum, but seeing as the reciprocal method works for any amount of branches, it would be best to stick to a single method for calculating equivalent resistance (Req).

If you want to calculate an unknown (Ru) or desired resistance for a certain branch, you can use the following formula.

Ru = Rk x Req / Rk – Req
where Ru is the unknown you would like to solve, Req is the desired equivalent resistance, and Rk is the known resistor that will be placed in parallel with Ru, achieving the desired resistance. This is known as the product over the difference.

Electronics No comments

Series Circuits

September 14th, 2006

A Series Circuit is defined by having a source, a path, and a load. There is only ever one path for current to flow. A series circuit can be viewed as a linear path, starting at the negative post of the power source, and continuing along the path, through each component, until it reaches the positive post of the power source.

To find the total resistance of a series circuit, you can simply add each resistance in the circuit, and you will have the total resistance. This is usually expressed as Rt or Resistance total. From now on when you see Rt, you know it is referring to total resistance in a series circuit. Another way or showing the formula for total resistance is:

Rt = R1 + R2 + R3… etc.

Another important method to find total resistance in any circuit, is the Ohm’s law formula R = V / I. If you know the voltage of the power source, and the total current (which is the same through any and all parts of a series circuit) then you can use it to find the circuit’s resistance.

Rt = Vt / It

You can also use this when you have a resistor’s voltage drop and you want to calculate it’s resistance.

Next we will look at how voltage is distributed in a series circuit. Each resistor “drops” a percentage of the total voltage as it travels through the circuit. To calculate these drops, we use the following formula.

Vr1 = Ir1 x R1

That is, to calculate resistor 1’s voltage drop (V), you take resistor 1’s current (I), times it’s resistance (R) value.

The largest value resistor in a series circuit drops the largest voltage, and the smallest resistor drops the least voltage. These drops occur because the current is the same, and each resistor’s drop is equal to current times resistance, or V = I x R

The voltage divider rule is the relation for a given resistor to it’s resistance value. If you take the resistor’s value divided by the total resistance of the circuit, and the multiply that by the total voltage, you end up with the voltage drop of that particular resistor. To find the voltage drop of resistor 1:

V1 = (R1 / Rt) x Vt

Kirchhoff’s voltage law states that the arithmetic sum of the voltages around a single circuit loop (V1 + V2… etc.) equals the applied voltage (Vt) it also states that the algebraic sum, incuding the source must equal zero.

Here is a link to a great site called All about circuits.

Electronics No comments

Electrical Quantities and Components

September 13th, 2006

For the most part, the metric system is used to measure and calculate electrical quantities in circuits and components. In the case of very large or small numbers, Engineering Notation is used.

.0000000000001 = 10 to the negative 12th power = pico (p)
.0000000001 = 10 to the negative 9th power = nano (n)
.0000001 = 10 to the negative 6th power = micro (u)
.0001 = 10 to the negative 6th power = milli (m)
1 = Base Units =
1,000 = 10 to the third power = kilo (k)
1,000,000 = 10 to the sixth power = mega (M)
1,000,000,000 = 10 to the ninth power = giga (G)
1,000,000,000,000 = 10 to the twelfth power = tera (T)

This makes it much easier to deal with large numbers and quickly cancel out exponents when doing calculations. The power of ten tells us how many places and which direction to move the decimal point. Say you have a 10,000 ohm resistor, this is easily written as a 10k resistor. Say you have a current that is .0000000009 amperes, it would be much easier to say you have 9 nA (nanoamps) of current. One thing to remember when dealing with these different values, it a few shortcuts you can take when calculating them.

Units divided by Kilo units, the answer will be in Milli units. This is useful when calculating current. I = V / R. The resistance is often in Kilo Units, and the current will be small enough to be measured in milli units. The same is true when finding resistance. R = V / I. Since we are taking Units divided by Milli units, the calculation for resistance will be in Kilo units. Lastly, this makes it also true that Milli units times Kilo units will leave you with Base units. This is used when finding voltage. If you think of the Ohm’s Law triangle, you see that as long as you remember what you are working with, there is no need to transpose the values. Your voltage is in base units (ex. 12v), your resistance is in Kilo (k) units (ex. 10k ohms), and finally your current is in Milli (m) units (ex. 4m amps).

Electrical Components

Every circuit must have at least three parts. A Source, Path and a Load. The Source is anything that supplies power to your circuit. Examples of a source are a DC battery, a DC power supply, an AC outlet on the wall in your home, etc. This is the part of your circuit that provides the potential difference (or voltage) to put the current through your Path, and to the Load, with the load being whatever you need to provide power to.

To put it correctly, you could say that the voltage is a potential difference (a difference of polarity between two points) which allows the current (the electrons) to move from the negative post through the circuit. This current runs through the path (your conductor such as wire) to the load, whether it is a resistor, a light bulb, an electric motor, and flows back to the positive post of the source to complete the path of the circuit.
Conductors are the “Path” for your current to flow. What type of conductor should you use? It depends on what you are building and what kind of electrical energy is need to support. Things to consider are the type of metal used, the physical dimensions of the wire, type of wire (solid, stranded or braided) and the wire’s insulation or lack thereof. THe ideal conductor would have zero resistance, just as the ideal insulator would have zero conductivity. Unfortunately this is not possible in the latter, but in the case of conductors, it is possible to cool the temperature to almost absolute zero ( -273 degrees C), and have it at an almost zero ohm resistance. This is known as Superconductivity.

Wire is gauged by the American Wire Gauge Standard (AWG) and is measured in Circular Mils. A Mil is about a thousandth of an Inch. To find the cross sectional area of a wire, take the following formula.

A = d squared

Where A is the cross sectional area you would like to find (this will be circular mils)
and d is the diameter of wire in mils.

Resistance for a given length also depends on the gauge of wire used. A 100 meter length of 10 gauge wire will have the same resistance as a 50 meter length of 13 gauge. The general rule of thumb is that for every three wire sizes larger, the current carrying capacity of the wire will double.

Resistors limit current and help determine current values for a given circuit, and can also divide voltages. The four main types of resistors are Carbon-Composition, Precision Film-type, Surface Mount “Chip”, and Wire-Wound. Carbon Composition resistors are available in ranges from 1 ohm to several million ohms. They are economical and are formed by two lead connections encapsulated in a carbon insulating material. Precision Film-Type resistors are more expensive, and as the name suggests, the values can be accurately controlled. Surface mount resistors look like tiny “chips” and are naturally better for smaller applications. Wire-Wound resistors are typically the larger resistors you find. Due to their size and construction, they are suitable for larger resistances and higher current.

The bands on a resistor tell you what the value of the resistor is, as well as the resistor tolerance (the amount the resistor’s value can fluctuate and still be considered good). In normal Four-Band resistors, the first band is the color code for the first significant figure (digit), the second band is the color code for the second significant figure (digit) and the third band is the color code for the decimal multiplier (number of zeros) to append to the end of the number. The fourth band is the color code for the tolerance level. Normal values are 5%, 10% and 20%.

Below is a color code chart for resistors

Black = 0
Brown = 1
Red = 2
Orange = 3
Yellow = 4
Green = 5
Blue = 6
Violet = 7
Gray = 8
White = 9

Now for the decimal multipliers.

Black = base units
Brown = 10 (1 zero added)
Red = 100 (2 zeros added)
Orange = 1,000 (3 zeros added)
Yellow = 10,000 (4 zeros added)
Green = 100,000 (5 zeros added)
Blue = 1,000,000 (6 zeros added)
Violet = 10,000,000 (7 zeros added)
Gray = 100,000,000 (8 zeros added)
White = 1,000,000,000 (9 zeros added)

Gold and Silver are used in the 3rd band to move the decimal place to the left.

Gold = .1
Silver = .01

Gold and Silver are also used in the fourth band to show the resistor’s tolerance (+ or – it’s shown value).

Gold = 5%
Silver = 10%
No Band = 20%

More to come, laters for now!

References:
Foundations of Electronics, by Russell L Meade

Electronics No comments

Basic Concepts of Electricity

September 11th, 2006

Matter is the substance that forms all physical things. Matter can be defined as anything that has mass and occupies space. Matter appears predominately as atoms. The three physical states of matter are solid, liquid and gas. The three chemical states of matter are elements, compounds and mixtures. An element is a substance that cannot be broken down into a smaller substance. A compound is a chemical reaction from the combination of two or more elements to. A mixture is a combination of two or more elements where the elements retain the same properties as when they are alone. No chemical change occurs.

Although science has identified other particles of the atom, the parts of the atom that are of interest to Electronics Technicians are the Proton, Neutron and Electron. Protons have a positive electrical charge and are located in the nucleus of the atom, along with the neutron. Electrons have a negative electrical charge and orbit the nucleus of the atom at trillions of times a second. Electrons are approximately 9×10 to the -28th power in weight, and are around 1800 times lighter than protons. Atoms contain an equal amount of protons and electrons. The number of protons in a single atom of an element is known as the Atomic Number. This number is usually shown on a Periodic Table of Elements.

Electrons orbitting around the nucleus of an atom align themselves in a stuctured manner known as shells. The first ring or shell contains up to two electrons. The second shell contains up to 8 electrons. The third shell contains up to 18 electrons. The outermost or valence shell, can never contain more than 8 electrons. The number of valence electrons determines it’s stability or instability, both electrically and chemically. The valence shell is full when it contains 8 electrons. Electrically, these outer electrons can be easily moved and are also referred to as free electrons.

When an electron leaves it’s original atom, it leave behind an atom that is no longer neutrally charged. This is called an Ion. With this example, since the electrons are negatively charged, the absence of it creates a positively charged ion. When the valence shell of an atom picks up extra electrons, it is considered a negatively charged ion. Common sources that can cause these electrons to move are friction, chemical energy, mechanical energy, magnetic energy and heat or light (solar) energy.

Conductors such as copper, have many free electrons. Copper contains a single electron on it’s valence shell, and due to it’s distance from the nucleus, it is loosely bound to the atom and is free to move across to other atoms of copper. Conductors contain one, two or three electrons on the outer shell. Insulators on the other hand, contain five to eight electron on the outer shell, and therefore do not easily allow electron movement. Glass is an example of an insulator. Semiconductors are somewhere inbetween conductors and insulators, allowing for restricted movement. Semiconductors have four electrons on their outer ring, such as silicon.

The unit of electrical charge is called the coulomb. The basic law of charges is that like charges repel, and opposited attract. When two bodies have a difference of electons between them, that means that one has a excess of electrons (negatively charged) and one has a deficiency of electrons (positively charged). This relative electrical charge is called the polarity.

Force = Charge 1 x Charge 2 / Distance squared

Coulomb’s Law stated that Force in newtons, is equal to the charge on the first body times the charge on the second body, divided by the distance between them squared. This states that the force or attraction between them is directly related to the product of their charges and inversely related to the distance between them. One coulomb of charge is equal to 6.25×10 to the 18th power, or 6,250,000,000,000,000,000 electrons.

The difference between two points having different charge levels is called a Potential Difference. This is also called Electromotive Force, due to the force moving the electrons from one place to the other. The unit of potential difference, or EMF, is called the Volt. This is merely the force capable of causing electron movement, by it’s difference between two points. Having this difference causes the electrons to move from the negative end to the positive end. The movement of the electrons is known as the Current, and is measured in Amperes, or amps.

One Ampere is a flow of one coulomb of charge for one second. The formula used is current (I) is equal to charge in coulombs (Q) divided by the Time (T) in seconds.

Current flowing through a conductor encounters molecular resistance. This is simply called Resistance (R) and is measured in Ohms. Types of conductor, physical size and length of that conductor, andthe use of semiconductors in the path all cotribute to the resistance of the material or circuit. An Ohm of resistance is the amount that limits the current to one ampere when on volt of electromotive force is applied.

A Circuit has three parts. There must be a source, a load, and a path for the current to flow. In addition, there may be a switch, or a means to turn the circuit on and off. The voltage source, such as a power supply or battery, provides the means to carry the electricity from the negative to positive points. The path, a conductor such as copper wire, provides a way to transport that electricity to the load, such as a light bulb or resistor.

When a switch is set to the off position, and the circuit is unpowered, this is considered to be an open circuit. Once that switch is turned on, it is considered a closed circuit, one that provides an unbroken path for current to flow.

The techniques of controlling electron flow to acheive a desired result in a circuit is the basis of all electronics.

Electronics No comments

My Lab Tools and Toolkit

September 5th, 2006

In the lab at school we are nicely set up. Each station has a Triple output power supply, function generator, digital multimeter and oscilloscope.

The Multimeters are all Tektronix CDM250’s as shown below.

multimeter_lab.jpg

The Oscilloscopes are Tektronix 2205-40 a 40mhz version of the models shown here.

oscilloscope_color_lab.jpgpowersupply_lab.jpg

The function generators are CFG250’s – 2 mhz

functiongenerator_lab.jpg
And the Power supplies are mostly CPS 250’s, but my station has a nice new power supply from digikey.

powersupply_lab.jpg
My Toolkit

Unfinished…

Electronics No comments